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1207. 独一无二的出现次数
题解代码
javascript
/**
* @param {number[]} arr
* @return {boolean}
*/
var uniqueOccurrences = function(arr) {
const hash = {}, hash1 = {}
for (let i = 0; i < arr.length; i++) {
hash[arr[i]] = (hash[arr[i]] || 0) + 1
}
for (let k in hash) {
if (hash[k] in hash1) return false
hash1[hash[k]] = k
}
return true
};