344. 反转字符串 #

原题链接：LeetCode 344. 反转字符串

题目描述 #

编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。

不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

示例 1：

**输入：**s = ["h","e","l","l","o"] 输出：["o","l","l","e","h"]

示例 2：

**输入：**s = ["H","a","n","n","a","h"] 输出：["h","a","n","n","a","H"]

提示：

1 <= s.length <= 105
`s[i]` 都是 ASCII 码表中的可打印字符

难度： Easy

题解代码 #

/**
 * @param {character[]} s
 * @return {void} Do not return anything, modify s in-place instead.
 */
var reverseString = function(s) {
  let temp
  for(let i = 0, len = s.length; i < len / 2; i++) {
    temp = s[len- i - 1]
    s[len - i - 1] = s[i]
    s[i] = temp
  }
};